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X^2+2X-5=3X^2-4X+1
We move all terms to the left:
X^2+2X-5-(3X^2-4X+1)=0
We get rid of parentheses
X^2-3X^2+2X+4X-1-5=0
We add all the numbers together, and all the variables
-2X^2+6X-6=0
a = -2; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·(-2)·(-6)
Δ = -12
Delta is less than zero, so there is no solution for the equation
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